《We Got Love》是sigala演唱的一首歌曲，以下是歌曲的歌詞：
We got love, yeah
Yeah, we got love
Yeah, we got love
Yeah, we got it, yeah
Yeah, we got love
Yeah, we got love
Yeah, we got it
Yeah, we got it, yeah
(Verse 1)
We been through the worst, we been through the best
Through the highs and lows, we been through the test
Through the pain and the pleasure, yeah
Through everything, together we stand
(Pre-Chorus)
Now it's time to give back, time to show them we care
'Cause it's a new day, let's start it with fire
We've been through so much, but we ain't done yet
(Chorus)
So here's to the future, here's to the past
Here's to the highs and lows, and everything in between
We got love, yeah, we got love
And we're gonna share it with the world tonight
We got love, yeah, we got it, yeah
And this fire in our hearts won't ever die
(Verse 2)
Time for us to create, for a new tomorrow
No time for selfishness, it's time to give more
Gonna leave this world a better place for our children and grandchildren
So they can understand what it means to have so much more
Than they'll ever have in this life but only you can fill my cup of desire for forever now sip解一元二次方程(x−5)2−3(x−5)−2=0．怎樣去括弧?能否說明依據是什麼？注意什麼？有同學根據以上規律將這個方程轉化為(x−3)(x−8)=0，這樣解對嗎？為什麼？這種解法有什麼優點？你能根據以上規律，將這個方程的解法寫出來嗎？
去括弧的方法是直接將小括弧內的式子與前面的係數相乘，同時去掉括弧；依據是乘法分配律；去括弧時要注意符號的變化；將方程轉化為$(x-3)(x-5+2)=0$，這樣解是對的；因為$(x-3)(x-5+2)$轉化為$(x-3)(x-3)$與$(x-3)(x+2)$的形式，符合一元二次方程的解法規律；$(x-5)^{2}-3(x-5)-2=0$的解法：$x^{2}-10x+4=0$，即$(x-5)^{2}=7$，解得$x_{1}=3$，$x_{2}=8$.解方程的一般思路是將高次方程轉化為一元一次方程或二元一次方程組．按照題目規律將方程寫成$(x-3)(x-5+2)=0$的形式即可求解．這種方法簡便易行．