"Juju What's Love" 是由 Juju 演唱的一首歌曲，其歌詞如下：
Juju:
What's love?
What's love?
What's love?
What's love?
What's love?
What's love?
What's love?
What's love?
(Chorus)
Baby, I don't need no game
To tell you what I really am
You can take my heart but you can't take my respect
I'm not your property to make or break
No, no, no, no, no, no, no, no
What's love? What's the meaning of it all?
Everyday we stray away from real reality.
Driving round in circles in a dysfunctional world.
Try to get along and yet it all goes wrong.
Tried to reach out and make a new friend.
Yet they just want to use you for your money and your fame.
(Verse 2)
I ain't got nobody, nobody but myself.
To blame for my misery.
I ain't got nobody, nobody but myself.
To rely on for help.
I ain't asking for a handout.
I ain't looking for a hand up.
I just want to be treated like a human being.
Not like a plaything or a sex toy.
(Chorus)
(Bridge)
If you really love me then you won't hurt me.
You will always respect me.
If you don't, then I don't want nothing to do with you.
No, no, no, no, no, no, no, no.
(Outro)
Juju - Juju What's Love? - Lyrics by Cathy Dennis and Sister2Sister Inc. ASCAP and S2S Publishing. © Copyright求解下列微分方程 dy/dx = -2x/(y+x^2) + x/(y+x^2)的通解，其中y'=dy/dx表示導數。這個問題可以通過分離變數來解決。我們可以將等式兩邊同時對x求導，以便找到未知函式的原函式。這個未知函式是f(x)，也就是通解中的y。這個方程可以通過以下步驟解決：解這個微分方程、求出原函式並給出通解。這是我們的解決方案：步驟1：首先將方程dy/dx = -2x/(y+x^2) + x/(y+x^2)兩邊同時對x求導。得到dy/dx的導數=-2(x^2+y)+x*(y'+1)。步驟2：通過以上結果得到dy = (-2x^2 + x(y'+1))dx的積分。將方程改寫為：積分後的表達式就是原函式的表達式，我們可以將它求出並得到通解。具體步驟如下：∫ dy = (1/3)(y^3-x^3) + C1；步驟3：將常數C1帶入原方程中求解得到通解為y = (C1+√[3(x^3+C)])/3。所以，這個微分方程的通解為y = (C1+√[3(x^3+C)])/3。其中C為任意常數。總結起來，我們可以通過求解微分方程、對結果進行積分和代入常數求解來得到通解。這就是解決這個問題的完整過程。希望這個過程能夠幫助你理解微分方程和通解的概念。