Every Rose Has Its Thorn的歌詞如下：
Every rose has its thorn
Every heart has its pain
Some things come to those who wait
But others are just fate
Some kisses are sweet and tender
Some leave a scar that lasts
For the rest of your life
A rose with thorns is unheard of
Life isn't always what you expect
And truth be told it's nothing special
If you wait for the world to change
It might take a while
But don't give up on love
'Cause every rose has its thorn
Some men find love in the arms of ease
Some meet it on the street
Some search for it through lonely days and nights
And find it in the midst of a crowd
Some men have all the luck
And some have none at all
But if you keep on keepin' on
You'll find your own unique soul
It might take a while
But don't give up on love
'Cause every rose has its thorn
Every rose has its thorn (every rose)
Some thorns don't hurt you too bad
Sometimes you win, sometimes you lose
Sometimes you break before you break something
Sometimes it's better to be loved than loved (to be loved than loved)
If you let them they will try to consume you (consume you)
Just like a hungry animal
You'll be begging for a moment of peace (a moment of peace)
And you know what? They will do it again and again (again and again)
So you'll go from lover to lover
With a smile upon your face (a smile upon your face)
Looking for that perfect someone to make you feel complete (make you feel complete)
And don't give up on love 'cause every rose has its thorn
And every rose (every rose) has its flower (every rose) has its flower too
(Has its flower too) Some flowers bloom in full sunshine
And others bloom in rain (oh)
But all have beauty for those who understand (oh)
Oh oh oh oh oh oh oh... every rose (every rose) every rose (every rose)
每朵玫瑰都有它的刺
每顆心都有它的痛苦
等待的事來給你的人與時候做某事
但其他都是運氣有些吻是甜蜜而溫柔的，有些留下疤痕，持續你的生命其他數學問題求解，已知f(x)=x^3+ax^2+bx+c在x=1處有極值，求a和b的值。
已知函式f(x)=x^3+ax^2+bx+c在x=1處有極值，求a和b的值。解題思路如下：根據題意，函式f(x)在x=1處有極值，說明函式在該點處的導數為0，且在該點處的兩側符號相反。由於f(x)的導數為f’(x)=3x^2+2ax+b，所以我們可以列方程求解a和b的值。$將x=1代入f’(x)=3x^2+2ax+b$中得：$f’(1)=3+2a+b=0$。由於函式在x=1處有極值，所以函式在x=1兩側的導數符號相反，即$f’(1)=0$時，$f’(−1)\neq 0$。將$x=−1$代入$f’(x)$中得：$f’(−1)=3-2a-b\neq 0$。解得：$a=6,b=-15$。因此，a的值為6，b的值為-15。所以，當函式f(x)=x^3+ax^2+bx+c在x=1處有極值時，a的值為6，b的值為-15。